Posted by Desoto61 [108.162.237.65] on Wednesday, July 20, 2016 at 12:14:52 :
In Reply to: So, 10psi = how hot? posted by Chris Case [108.162.215.96] on Wednesday, July 20, 2016 at 08:10:52 :
Per Wikipedia, the problem is that this is basically an isotropic process, you have a fixed volume and are adding air (n) to increase pressure (P), so if you look at the table you can relate temperature for two known pressures (or in your case a ratio of the two pressures). Since it's just air ã is typically 1.4 so:
T2 = T1(P2/P1)^((ã − 1)/ã)
where P1 is atmospheric pressure = 14.7 psi
so P2 at 10 psig = 24.7 psi.
If you assume 70 degree inlet air then increasing the pressure 10 psi = 81.2 degrees.
Of course this is the "ideal gas" law, and real air isn't an ideal gas, nor is whatever is compressing it an isotropic process. The turbo adds heat (mechanical and thermal) during the compression process. But it's a starting point, at least assuming I did any of that correctly, it's been a while!
FYI, I keep my HP in my desk, too big for my pocket, but I do have an emulator on my phone! Love me some RPN Ha!
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