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Posted by M Fanoni [70.199.64.241] on Tuesday, February 12, 2013 at 12:03:07 :
In Reply to: I used a round number..... more: posted by Chris Case [75.36.35.9] on Tuesday, February 12, 2013 at 08:46:06 :
I like the test idea. That way the variables are eliminated and you can just determine the real size of a required shear pin. The value for shear/tensile will be .6 for steels.
Too many losses and variance between machines! Testing is usually the "easy" way out since you can gloss over a lot in terms of engineering, but I think I can convince myself it is ok in this situation.